Select Page

# The Distributive Property

Home >> Online Math Tutoring >> Precalculus Tutor >> The Distributive Property

A Linear equation is an equation in which the highest exponent of the variable present in the equation is one. When we draw the graph of the linear equation, it forms a straight line.

Example:   x + 3 = 7, which is linear equation since the highest power of the variable, x present in the equation is 1.

### How many solutions are there to a linear equation?

The solution of a linear equation is a value of the variable which satisfies the linear equation i.e. which makes the linear equation true.

A linear equation can have one, zero or infinite solution. We illustrate this with some examples.

1. Linear equations with one solution.

Example 1: Consider the equation 7x – 35 = 0.

On solving we have, 7x = 35 or x = 5. The above linear equation is only true if x = 5.

Hence the given linear equation has only one solution i.e. x = 5.

1. Linear equations with zero solution i.e. no solution.

Example 2: Consider the equation 7x – 35 = 5x + 2x – 27.

On solving we have, 7x – 35 = 7x – 27

Subtracting 7x from both sides, 7x – 7x – 35 = 7x – 7x – 27

We have -35 = -27, which is a false statement since it can’t be true for any value of the variable x.

Hence, the given linear equation has zero solution or the number of solutions is zero.

1. Linear equations with infinite solutions.

Example 3: Consider the equation 25x – 35 = 5(5x + 4) – 55.

On solving we have, 25x – 35 = 25 x + 20 – 55 or 25x – 35 = 25x – 35.

Subtracting 25x from both sides, 25x – 25x – 35 = 25x – 25x – 35

We have -35 = -35, which is a true statement and it will be true for any value of the variable x. Hence the given linear equation has Infinite solutions or the number of solutions is infinite.

There are different forms of writing a linear equation. There is a way for solving the different forms of linear equations. For solving equations, we try to separate the variable to find the value of the variable. This is done using inverse operations.

# 4 + 3 = 7.

### When should you use the distributive property when solving an equation?

Distributive property is used to solve linear equations before separating the variables and it makes the process of finding the solution easier.

1) a(b + c) = ab + ac

2) a(bc) = abac

Example 1: Solve for x: 3(x – 5) = 24

Using the distributive property, 3(x) – 3(5) = 24

3x – 15 = 24

Adding 15 on both sides, we have 3x – 15 + 15 = 24 + 15

3x = 39

Dividing both sides by 3,                                   x = 13

Example 2: Solve for x: 2(x + 7) + x = 26

Using the distributive property, 2(x) + 2(7) + x = 26

2x + x + 14 = 26 or 3x + 14 = 26

Adding 14 on both sides, 3x + 14 – 14 = 26 – 14

3x = 12

Dividing both sides by 3,x = = 4 .

Example 3: A gym charges a $50 activation fee and$17 per month for a membership. If twice the total money you spend is $474, for how many months, do you have gym membership? Let x be the number of months for which the membership of gym is taken. Then we have, 2(17x + 50) = 474 Using the distributive property, 2(17x) = 2(50) = 474 34x + 100 – 100 = 474 – 100 Subtract 100 on both sides 34x = 374 Divide by 34 on both sides, x = = 11 Hence the gym membership was taken for 11 months. ## Check Point Solve each of the equation using distributive property and combining like terms. 1. 2(x + 7) + 5x = 28 2. 2(y – 1) + 3y = 3 3. 2(3z – 1) + 2(4z + 5) = 8 4. 8 + 3(x + 2) = 5(x – 1) 5. A gift pack contains 3 identical t-shirts and a hat. If the hat costs$21 and Martin buys two such gift packs for $120. Find the cost of each t-shirt. 6. A company sells their laptops at a price of$50 more from the manufacturing cost. If they sell 20 laptops for a total cost of $3,000, find the manufacturing cost of each laptop. 7. A TV sports channel subscription costs$10 per month plus a $25 sign-up fee. If Martin paid a bill of$75, how many months subscription did he purchase?
1. x = 2
2. y = 1
3. z = 0
4. x = 19/2
5. Cost of each t-shirt = $13 6. Manufacturing cost of each laptop =$100.
7. Martin purchased 5 months subscription.

## Personalized Online Tutoring

eTutorWorld offers affordable one-on-one live tutoring over the web for Grades 2-12, Test Prep help for Standardized tests like SCAT, CogAT, SSAT, SAT, ACT, ISEE and AP. You may schedule online tutoring lessons at your personal scheduled times, all with a Money-Back Guarantee. The first one-on-one online tutoring lesson is always FREE, no purchase obligation, no credit card required.

For answers/solutions to any question or to learn concepts, take a FREE Demo Session.

No credit card required, no obligation to purchase.
Just schedule a FREE Sessions to meet a tutor and get help on any topic you want!

## Pricing for Personalized Online Tutoring

Tutoring Package Validity Grade (1-12), College
5 sessions 1 Month $119 1 session 1 Month$24
10 sessions 3 months $229 15 sessions 3 months$339
20 sessions 4 months $429 50 sessions 6 months$999
100 sessions 12 months \$1949

## IN THE NEWS Our mission is to provide high quality online tutoring services, using state of the art Internet technology, to school students worldwide.